ATC 2010 Is Over

The Automated Trading Championship 2010 (MetaQuotes‘ contest among MetaTrader 5 expert advisors) is now officially over. The last trading day was on December 24 and it has failed to bring any surprises to the overall results in the prize positions. The first three places of this Forex championship are the following:

  • bobsley (Russian Federation) — with the final balance of $77,103. Was a leader of the race for about 1 month. Used a single-currency EUR/USD EA based on moving averages.
  • Buter (Russian Federation) — $62,578. Tried to conquer the first place few times but bobsley didn’t allow him to set the roots there. Also a single-currency EUR/USD EA.
  • forez (France) — $50,898. The struggle for the third place was intense but forez has managed to get it, surpassing his closest rival by more than $4,000. He also used a single-currency EUR/USD expert advisor. The guy has also scored the lowest relative drawdown (28.37%) of all the EAs that at least doubled the balance and closed at least 30 positions. It’s a very stable result for the championship, where everyone seems to be risking everything with each trade.
  • I’d like to congratulate the winners and all the participants for their strife to victory. As for my own EA — it landed on the 245th place with $1,611 balance, this is better than my 2008 result (401st place) but worse than my 2007 result (179th place). But that doesn’t really matter much as all my participating EAs have been losing. That’s why I still trade only manually on real accounts. This time it was a rather simple EA that tried to capture the trend changes by checking last three bars (forming either a top or a bottom), it was also self-adapting by switching the trade direction after a certain amount of losses in a row. You can now download the EA if you want.
    Anyway, I’m looking forward to participate in ATC 2011 next year and get at least a positive result there :).

    If you have some questions or comments regarding ATC 2010 Forex contest, please, feel free to reply using the form below.

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